3b^2-27b+63=3

Solution for 3b^2-27b+63=3 equation:

Simplifying
3b2 + -27b + 63 = 3

Reorder the terms:
63 + -27b + 3b2 = 3

Solving
63 + -27b + 3b2 = 3

Solving for variable 'b'.

Reorder the terms:
63 + -3 + -27b + 3b2 = 3 + -3

Combine like terms: 63 + -3 = 60
60 + -27b + 3b2 = 3 + -3

Combine like terms: 3 + -3 = 0
60 + -27b + 3b2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(20 + -9b + b2) = 0

Factor a trinomial.
3((4 + -1b)(5 + -1b)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Subproblem 2
Set the factor '(5 + -1b)' equal to zero and attempt to solve:

Simplifying
5 + -1b = 0

Solving
5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1b = 0 + -5
-1b = 0 + -5

Combine like terms: 0 + -5 = -5
-1b = -5

Divide each side by '-1'.
b = 5

Simplifying
b = 5
Solution
b = {4, 5}